1 write to doubleID
System.Xml (1)
System\Xml\Serialization\XmlSerializationReader.cs (1)
218doubleID = r.NameTable.Add("double");
5 references to doubleID
System.Xml (5)
System\Xml\Serialization\XmlSerializationReader.cs (5)
329else if ((object) typeName.Name == (object) doubleID) 396else if ((object) typeName.Name == (object) doubleID) 565else if ((object)type.Name == (object)doubleID) 636else if ((object)type.Name == (object)doubleID) 723else if ((object)type.Name == (object)doubleID)