1 write to choiceArrayName
System.Xml (1)
System\Xml\Serialization\XmlSerializationReader.cs (1)
2020this.choiceArrayName = "choice_" + this.arrayName;
3 references to choiceArrayName
System.Xml (3)
System\Xml\Serialization\XmlSerializationReader.cs (3)
2032this.choiceArraySource = outerClass.GetArraySource(mapping.TypeDesc, this.choiceArrayName, multiRef); 2034string a = choiceArrayName; 2108get { return choiceArrayName; }