3 references to String100
System.ServiceModel (3)
System\ServiceModel\ServiceModelStringsVersion1.cs (1)
611
case 100: return
String100
;
System\ServiceModel\XD.cs (2)
450
this.ReferenceParameters = dictionary.CreateString(ServiceModelStringsVersion1.
String100
, 100);
1759
public const string ReferenceParameters = ServiceModelStringsVersion1.
String100
;