1 write to timeoutString1Index
System.ServiceModel (1)
System\ServiceModel\Channels\ReliableMessagingHelpers.cs (1)
1468
set { this.
timeoutString1Index
= value; }
2 references to timeoutString1Index
System.ServiceModel (2)
System\ServiceModel\Channels\ReliableMessagingHelpers.cs (2)
1572
if (this.
timeoutString1Index
!= null)
1575
new TimeoutException(SR.GetString(this.
timeoutString1Index
, this.originalTimeout)));