3 references to String75
System.ServiceModel (3)
System\ServiceModel\ServiceModelStringsVersion1.cs (1)
586
case 75: return
String75
;
System\ServiceModel\XD.cs (2)
786
this.FaultRole = dictionary.CreateString(ServiceModelStringsVersion1.
String75
, 75);
1979
public const string FaultRole = ServiceModelStringsVersion1.
String75
;