3 references to String482
System.ServiceModel (3)
System\ServiceModel\ServiceModelStringsVersion1.cs (1)
993
case 482: return
String482
;
System\ServiceModel\XD.cs (2)
1716
this.Actor = dictionary.CreateString(ServiceModelStringsVersion1.
String482
, 482);
1961
public const string Actor = ServiceModelStringsVersion1.
String482
;