3 references to String25
System.ServiceModel (3)
System\ServiceModel\ServiceModelStringsVersion1.cs (1)
536
case 25: return
String25
;
System\ServiceModel\XD.cs (2)
1555
this.Upper = dictionary.CreateString(ServiceModelStringsVersion1.
String25
, 25);
2404
public const string Upper = ServiceModelStringsVersion1.
String25
;