3 references to String69
System.ServiceModel (3)
System\ServiceModel\ServiceModelStringsVersion1.cs (1)
580
case 69: return
String69
;
System\ServiceModel\XD.cs (2)
780
this.Role = dictionary.CreateString(ServiceModelStringsVersion1.
String69
, 69);
1973
public const string Role = ServiceModelStringsVersion1.
String69
;