3 references to String400
System.ServiceModel (3)
System\ServiceModel\ServiceModelStringsVersion1.cs (1)
911
case 400: return
String400
;
System\ServiceModel\XD.cs (2)
562
this.PreparedAction = dictionary.CreateString(ServiceModelStringsVersion1.
String400
, 400);
1841
public const string PreparedAction = ServiceModelStringsVersion1.
String400
;