2 references to CreateJsonResponse
System.ServiceModel.Web (2)
System\ServiceModel\Dispatcher\WebErrorHandler.cs (1)
77
fault = context.
CreateJsonResponse
(webFaultException.DetailObject, new DataContractJsonSerializer(webFaultException.DetailType, webFaultException.KnownTypes));
System\ServiceModel\Web\WebOperationContext.cs (1)
96
return
CreateJsonResponse
<T>(instance, serializer);