1 write to currentItem
System.ServiceModel.Discovery (1)
System\ServiceModel\Discovery\RandomDelayQueuedSendsAsyncResult.cs (1)
103(thisPtr, r) => thisPtr.currentItem = thisPtr.itemQueue.EndDequeue(r));
2 references to currentItem
System.ServiceModel.Discovery (2)
System\ServiceModel\Discovery\RandomDelayQueuedSendsAsyncResult.cs (2)
70if (this.currentItem == null) 126(thisPtr, t, c, s) => thisPtr.OnBeginSendItem(thisPtr.currentItem, t, c, s),