1 write to sendItemStep
System.ServiceModel.Discovery (1)
System\ServiceModel\Discovery\RandomDelayQueuedSendsAsyncResult.cs (1)
125
sendItemStep
= RandomDelayQueuedSendsAsyncResult<TItem>.CallParallel(
2 references to sendItemStep
System.ServiceModel.Discovery (2)
System\ServiceModel\Discovery\RandomDelayQueuedSendsAsyncResult.cs (2)
123
if (
sendItemStep
== null)
130
return
sendItemStep
;