1 write to dequeueStep
System.ServiceModel.Discovery (1)
System\ServiceModel\Discovery\RandomDelayQueuedSendsAsyncResult.cs (1)
101
dequeueStep
= RandomDelayQueuedSendsAsyncResult<TItem>.CallAsync(
2 references to dequeueStep
System.ServiceModel.Discovery (2)
System\ServiceModel\Discovery\RandomDelayQueuedSendsAsyncResult.cs (2)
99
if (
dequeueStep
== null)
106
return
dequeueStep
;