2 references to Any
System.Data.SqlXml (2)
System\Xml\Xsl\Xslt\QilGenerator.cs (1)
1777
Debug.Assert(num.Level == NumberLevel.
Any
);
System\Xml\Xsl\Xslt\XsltLoader.cs (1)
1644
case "any" : level = NumberLevel.
Any
; break;